SOLUTION: A metra commuter train leaves union station in chicago at 12 noon. Two hours later, an amtrack train leaves on the same track, traveling at an average speed that is 50 miles per ho
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Question 152161This question is from textbook precalculus
: A metra commuter train leaves union station in chicago at 12 noon. Two hours later, an amtrack train leaves on the same track, traveling at an average speed that is 50 miles per hour faster than the metra train. At 3pm, the amtrack train is 10 miles behind the commuter train. how fast is each going? This question is from textbook precalculus
You can put this solution on YOUR website! A metra commuter train leaves union station in chicago at 12 noon. Two hours later, an amtrack train leaves on the same track, traveling at an average speed that is 50 miles per hour faster than the metra train. At 3pm, the amtrack train is 10 miles behind the commuter train. how fast is each going?
:
Let s = speed of the commuter train
then
(s+50) = speed of Am-trac
:
Dist traveled by the commuter train at 3pm = 3s
Dist traveled by am-trac = 1(s+50)
:
Write a distance equation: dist = time * speed
:
commuter dist = Amtrac dist + 10 mi
3s = 1(s+50) + 10
3s = s + 50 + 10
3s - s = 60
2s = 60
s =
s = 30 mph is the commuter train
then
30 + 50 = 80 mph is Amtrac
;
:
Check solution by finding the distance each has traveled at 3 pm
3 * 30 = 90
1 * 80 = 80
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differ = 10 mi
