Question 151996: Lainey is 5 years old than her sister,mary. In 2 years she will be twice as old as her. What is their ages.
Answer by orca(409)   (Show Source):
You can put this solution on YOUR website! Let x be the age of Mary now. Then Lainey's age now is x + 5.
In two years, Mary's age will be x + 2
In two years, Lainey's age will be x + 5 + 2 = x + 7
As in two years Lainey will be twice as old as mary will be, we have
x + 7 = 2(x + 2)
Solving for x, we have:
x + 7 = 2x + 4
x = 3
So Mary is 3 now and Lainey is 8 now.
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