Question 151866: I can't figure how to factor completely.
216p^3 - 1
Choices are
(6p - 1)(36p^2 + 6p + 1)
(216p - 1)(p^2 + 6p + 1)
(6p + 1(36p^2 - 6p + 1)
(6p - 1)(36p^2 + 1)
Help would be greatly appreciated. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! factor completely.
216p^3 - 1
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The form of your problem is x^3 - y^3 where x = 6p and y = 1.
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That form factors as (x-y)(x^2+xy+y^2)
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So the factors of your problem are:
(6p - 1)((6p)^2 + (6p)(1) + 1^2)
= (6p-1)(36p^2 + 6p + 1)
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Cheers,
Stan H.
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