SOLUTION: Hi. I was wondering if you could help me solve a few math problems. I am about to enter Algebra 2, but I have forgotten everything that I learned from Algebra 1, even simplifying!

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Question 151836: Hi. I was wondering if you could help me solve a few math problems. I am about to enter Algebra 2, but I have forgotten everything that I learned from Algebra 1, even simplifying! I'm hoping to use a few solved problems as examples of how to solve the rest of my work. If you are not able to answer all of them I will understand and thank you for at least trying. I would really appreciate whatever help you can provide.
1. (x^3 + 3x^2 - 2) + (5x^3 + x +8) - (9x^3 - x^2 +4)
2. (x - 2)^2 = 25
3. (-3x^2y)^2
4. 2x + 5y < 10
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
1. (x^3 + 3x^2 - 2) + (5x^3 + x +8) - (9x^3 - x^2 +4)
;
Remember that removing the brackets with neg in front, changes the signs
x^3 + 3x^2 - 2 + 5x^3 + x + 8 - 9x^3 + x^2 - 4
;
Group like terms
x^3 + 5x^3 - 9x^3 + 3x^2 + x^2 + x - 2 + 8 - 4
:
Combine like terms:
-3x^3 + 4x^2 + x + 2
:
:
2. (x - 2)^2 = 25; this one has an equal sign so we can solve it:
FOIL
x^2 - 4x + 4 - 25 = 0
x^2 - 4x - 21 = 0
Factor
(x-7)(x+3) = 0
x = +7
x = -3; check both solutions in the original equation
:
:
3. (-3x^2y)^2
Square each term inside the brackets, mult exponents raised to another exponent
9x^4y^2
:
4. 2x + 5y < 10
5y < 10 - 2x; subtract 2x from both sides
y < *10 - x; divided both sides by 5
y < 2 - x