SOLUTION: (x/x^2 - 16) ÷ (x^3/x^2 - 14x + 40)

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Question 151807This question is from textbook Algebra 1 an incremental development
: (x/x^2 - 16) ÷ (x^3/x^2 - 14x + 40) This question is from textbook Algebra 1 an incremental development

Answer by orca(409) About Me  (Show Source):
You can put this solution on YOUR website!
[x/(x^2 - 16)]/[x^3/(x^2 - 14*x + 40)]
=[x(x^2-14*x+40)]/[x^3(x^2-16)]
=[x(x-10)(x-4)]/[x^3(x+4)(x-4)]
=(x-10)/[x^2(x+4)]