SOLUTION: It is an odd two-digit number,the sum of its digits is 8,the sum of the squares of its digits is 50. What is it?

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Question 151775: It is an odd two-digit number,the sum of its digits is 8,the sum of the squares of its digits is 50. What is it?
Found 2 solutions by prasd7982, jojo14344:
Answer by prasd7982(1) About Me  (Show Source):
You can put this solution on YOUR website!
It is an odd two-digit number,the sum of its digits is 8,the sum of the squares of its digits is 50. What is it?
ANS :my ans is either 71 or 17

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
The answer is right, 71 or 17 (shown in Answer#111569)
But we'll try to show the person who addressed the question how we arrived to that answer if you don't mind.
Let, x ----------> 1st digit
y ------------> 2nd digit
1st condition: the sum of its digit is 8,
x%2By=8 -----------> eqn 1
2nd condition: the squares of its digits is 50,
x%5E2%2By%5E2=50 -------> eqn 2
IN EQN 1 WE GET, y=8-x and substitute in eqn 2:
x%5E2%2B%288-x%29%5E2=50 ------------> working eqn
x%5E2%2B64-16x%2Bx%5E2-50=0
2x%5E2-16x%2B14=0 --> divide the whole eqn by 2,
x%5E2-8x%2B7=0 -------> it's perfect square that equals to:
%28x-7%29%28x-1%29=0, got 2 values:
x%5B1%5D=7, x%5B2%5D=1
Go back eqn 1,
x%5B1%5D%2By%5B1%5D=8 -------> 7%2By%5B1%5D=8 ---> y%5B1%5D=8-7
y%5B1%5D=1
AND,
x%5B2%5D%2By%5B2%5D=8 -------> 1%2By%5B2%5D=8 ----> y%5B2%5D=8-1
y%5B2%5D=7
SO THERE YOU GO, THE ANSWERS EITHER x%5B1%5Dy%5B1%5D=71 OR x%5B2%5Dy%5B2%5D=17
To check, this time try eqn 2: use values of x%5B1%5Dy%5B1%5D or x%5B2%5Dy%5B2%5D
1%5E2%2B7%5E2=50
1%2B49=50 ------------> 50=50
Thank you,
Jojo