SOLUTION: In 1996 23/50 of all accidental deaths in the US resulted from car accidents how many deaths were accidental in 1996 23/50 divided into the 43,194 were car accidents x would be d

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: In 1996 23/50 of all accidental deaths in the US resulted from car accidents how many deaths were accidental in 1996 23/50 divided into the 43,194 were car accidents x would be d      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 151550: In 1996 23/50 of all accidental deaths in the US resulted from car accidents how many deaths were accidental in 1996
23/50 divided into the 43,194 were car accidents
x would be deaths that were accidental How do I put this in an equation

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
If 43,194 were car accidents and 23%2F50 resulted in deaths, so the total will be: x=deaths
x=%2823%2F50%29%2A43194=19869.24 = approximate 19,870 deaths(it's over 19869)
To check it out:
%2823%2F500%29%2A100 = 46%, and
46% of 43194 = 0.46%2A43194=19869.24
Thank you,
Jojo