SOLUTION: thank you in advance for your help with helping me confirm or deny my work. I need to write this in standard form. m=4/3; (-4,-5) I came up with 4a-3b=-1. Am I on the right tr

Algebra ->  Graphs -> SOLUTION: thank you in advance for your help with helping me confirm or deny my work. I need to write this in standard form. m=4/3; (-4,-5) I came up with 4a-3b=-1. Am I on the right tr      Log On


   

Question 151492This question is from textbook college algebra
: thank you in advance for your help with helping me confirm or deny my work. I need to write this in standard form. m=4/3; (-4,-5) I came up with 4a-3b=-1. Am I on the right track. This question is from textbook college algebra

Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

If you want to find the equation of line with a given a slope of 4%2F3 which goes through the point (-4,-5), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y--5=%284%2F3%29%28x--4%29 Plug in m=4%2F3, x%5B1%5D=-4, and y%5B1%5D=-5 (these values are given)


y%2B5=%284%2F3%29%28x--4%29 Rewrite y--5 as y%2B5


y%2B5=%284%2F3%29%28x%2B4%29 Rewrite x--4 as x%2B4


y%2B5=%284%2F3%29x%2B%284%2F3%29%284%29 Distribute 4%2F3

y%2B5=%284%2F3%29x%2B16%2F3 Multiply 4%2F3 and 4 to get 16%2F3

y=%284%2F3%29x%2B16%2F3-5 Subtract 5 from both sides to isolate y

y=%284%2F3%29x%2B1%2F3 Combine like terms 16%2F3 and -5 to get 1%2F3 (note: if you need help with combining fractions, check out this solver)

3y=4x%2B1 Multiply every term by the LCD 3 to clear the fractions.


-4x%2B3y=1 Subtract 4x from both sides.


4x-3y=-1 Multiply every term by -1 (this will make the "x" coefficient positive).



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Answer:
So the equation in standard form that has a slope m=4%2F3 and goes through the point (-4,-5) is

4x-3y=-1

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Yes, you are on the right track.
Cheers,
Stan H.