|
Question 151455: I am extremely confused with how to solve fractions...especially fractions with two variables.
1/2 x + 1/3 y = 1/3
1/6 x + 1/3 y = 2/9
Found 3 solutions by oscargut, stanbon, JENNYRULES:
Answer by oscargut(2103)   (Show Source):
You can put this solution on YOUR website! 1/2 x + 1/3 y = 1/3
1/6 x + 1/3 y = 2/9 (-3)
1/2 x + 1/3 y = 1/3
-1/2 x -1 y = -2/3
adding both eq we have
-2/3 y = -1/3 then y=1/2
-1/2 x -1/2 =-2/3
-1/2 x = -2/3+1/2= -4/6 +3/6 =-1/6
x= 1/3
Solution: x=1/3 and y=1/2
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! 1/2 x + 1/3 y = 1/3
1/6 x + 1/3 y = 2/9
-----------------------
Fractions are a nuisance; get rid of them.
Multiply thru 1st by 6
Multiply thru 2nd by 18
-------------------------
3x + 2y = 2
3x + 6y = 4
---------------
Subtract 1st from 2nd to get:
4y = 2
y = 1/2
-----------
Substitute into 3x+2y = 2 to solve for "x":
3x + 2(1/2) = 2
3x = 1
x = 1/3
---------------
Cheers,
Stan H.
Answer by JENNYRULES(2) (Show Source):
You can put this solution on YOUR website! First of all, there are several different methods they will teach you to solve these equations/expressions, etc. All of the methods result in the same answer, though.
I'm not going to take you step-by-step like everyone else here, who truly understand all this stuff. Instead, I offer something much more valuable and it's a link I keep handy on my desktop and use very often. Go to http://www.myalgebra.com/algebra_solver.aspx and you will see that this site is an absolute God-send!!!
For example: I simply plugged in the exact information you gave me just like it's typed and selected "solve" and it asks what method to use and I just piced the substitution method just for the heck of it.
What ever method used...... it shows you the work and gives you the answer.
So, it gave me the following answer, showing me the work, as well:
x= 1/3
y= 1/2
Hope this site helps you guys as much as it has me! LOL!
|
|
|
| |
