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| Question 151452:  1) ABCD is a parallelogram if AB = 2 AD and P is the midpoint of AB.prove that angle CPD = 90.
 2) If the diagonal PR and QS of a parallelogram PQRS are equal, prove that PQRS is a rectangle.
 3) PQRS is a parallelogram. PS is produced to M so that SM = SR and MR is produced to meet PQ produced to N. Prove that QN = QR.
 Answer by orca(409)
      (Show Source): 
You can put this solution on YOUR website! 1) ABCD is a parallelogram if AB = 2 AD and P is the midpoint of AB.prove that angle CPD = 90. SOLUTION:
 In isosceles triangle APD,
 < APD = < ADP = (180 - < A)/2 = 90 - < A/2
 In isosceles triangle PCB,
 < BPC = < BCP = (180 - < B)/2 = 90 - < B/2
 Next express < DPC in terms of < A and < B.
 < DPC = 180 - < APD - < BPC = 180 - (90 - < A/2) - (90 - < B/2) = < A/2+ < B/2
 = (< A + < B)/2
 Note that in any parallelogram the sum of any two adjacent angles is 180. so:
 < A + < B = 180
 Therefore
 < DPC = (< A + < B)/2 = 180/2 = 90
 ALTERNATIVE SOLUTION:
 First prove that
 PD bisects < D
 PC bisect < C
 (Let Q be the midpoint of CD. As triangle APD and QPD are congruent, so < ADP = < QDP. For the same reason < BCP = < QCP)
 Next
 < PDQ = < D/2
 < PCQ = < C/2
 Thus < PDQ + < PCQ = < D/2 + < C/2 = (< D + < C)/2 = 180/2 = 90.
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 2) If the diagonal PR and QS of a parallelogram PQRS are equal, prove that PQRS is a rectangle.
 SOLUTION:
 We need to prove its angles are 90 degree.
 First prove that triangle PQR and triangle QRS are congruent.(Reason: PQ = SR, QR = QR and PR = QS)
 So < Q = < R
 Next note that < Q + < R = 180.
 As < Q = < R, < Q = < R = 90.
 So PQRS is a rectangle.
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 PQRS is a parallelogram. PS is produced to M so that SM = SR and MR is produced to meet PQ produced to N. Prove that QN = QR.
 SOLUTION:
 We need to prove triangle QNR is an isosceles triangle.
 First show that < N = < SRM and < QRN = < M ( ? )
 Next show that < SRM = < M ( ? )
 Conclusion: < N = < QRN ( ? ), So triangle QNR is isosceles.
 
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