SOLUTION: how would you... A.) use the distributive property to solve and create a binomial to set up the FOIL method B.) Solve with the FOIL method could you break it down step by step?

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: how would you... A.) use the distributive property to solve and create a binomial to set up the FOIL method B.) Solve with the FOIL method could you break it down step by step?      Log On


   



Question 151323: how would you...
A.) use the distributive property to solve and create a binomial to set up the FOIL method
B.) Solve with the FOIL method
could you break it down step by step?
4x(x^2-2x+5)

Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A.) use the distributive property to solve and create a binomial to set up the FOIL method
(x+a)(x+b)
= (x+a)x + (x+a)b
= xx + ax + bx + ab
Which is F--O--I--L
================================
B.) Solve with the FOIL method
could you break it down step by step?
= 4x(x^2-2x+5)
= 4x*x^2 -4x*2x + 4x*5
============================
Cheers,
Stan H.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
This problem does not involve FOILing, but involves distribution (you use FOIL when you have two binomials). So I would double check the problem.


Anyways, here's how you would simplify the problem.


4x%28x%5E2-2x%2B5%29 Start with the given expression.


4x%28x%5E2%29%2B4x%28-2x%29%2B4x%285%29 Distribute.


4x%5E3%2B4x%28-2x%29%2B4x%285%29 Multiply 4x and x%5E2 to get 4x%5E3


4x%5E3-8x%5E2%2B4x%285%29 Multiply 4x and -2x to get -8x%5E2


4x%5E3-8x%5E2%2B20x Multiply 4x and 5 to get 20x


So 4x%28x%5E2-2x%2B5%29 distributes and simplifies to 4x%5E3-8x%5E2%2B20x


In other words, 4x%28x%5E2-2x%2B5%29=4x%5E3-8x%5E2%2B20x