SOLUTION: {{{-x<2x+3<-8x+3}}}

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Question 151259: -x%3C2x%2B3%3C-8x%2B3



Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!


-x%3C2x%2B3%3C-8x%2B3

Procedure for FIRST%3CSECOND%3CTHIRD

1. Solve FIRST%3CSECOND
2. Solve SECOND%3CTHIRD
3. Solve FIRST%3CTHIRD

Put all three on number lines and take 
what is common to all three number
lines:

Solve the first two only:

-x%3C2x%2B3

Add +x to both sides:

-x%2Bx%3C2x%2B3%2Bx

0%3C3x%2B3

Add -3 to both sides:

0-3%3C3x%2B3-3

-3%3C3x

Divide through by +3 (doesn't reverse inequality)

-1%3Cx

which is the same as x%3E-1

Draw the graph of that on a number line:

---------------------------------------------


Next solve the second and third only:

 2x%2B3%3C-8x%2B3

Add -3 to all three sides:

2x%2B3-3%3C-8x%2B3-3

2x%3C-8x

Add +8x to both sides:

2x%2B8x%3C-8x%2B8x

10x%3C0

Divide both sides by 10:

x%3C0

----

-x%3C-8x%2B3

x-x%3C-8x%2B3-x

0%3C-9x

Divide both sides by -9 (reverses the inequality)

0%3Ex

So that gave us the same inequality as the second.

Therefore we have only these two inequalities:

-1%3Cx  and x%3C0

They can be written together as

-1%3Cx%3C0 or in interval notation as (-1,0).

Edwin