Question 151147This question is from textbook
: Can someone please help me with these problems-
7x+3>9x-5
and
5x-5<2x+10 This question is from textbook
You can put this solution on YOUR website! 7x+3>9x-5
Solving inequalities is just like solving equalities. The only difference is when you multiply or divide both sides by a negative number, in which case, you will have to reverse the direction of the inequality sign. For example:
-2x > 6
Dividing both sides by (-2) :
-2x/(-2) < 6/(-2) (Take note that the inequality sign is reversed from
">" to "<".)
x < -3
Now to your question :
1) 7x+3 > 9x-5
7x - 9x > -5 -3 ( By Transposition )
-2x > -8
-2x /(-2) < -8 /(-2) ( Dividing both sides by -2 )
x < 4
=======
You can put this solution on YOUR website! Solving any equations with "greater than" or "less than" signs is pretty much the same as solving a normal equation.
The only time inequalities don't act the same as normal equations is when each side is multiplied by a negative number. If that happens, a "greater than" sign becomes a "less than" sign or vice versa.
(
