SOLUTION: I dont understand how I should solve these by factoring; x^2-5x+6=0, 2x^2-9x-5=0, 3x^2+5x-2=0, could someone please help me with them?

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: I dont understand how I should solve these by factoring; x^2-5x+6=0, 2x^2-9x-5=0, 3x^2+5x-2=0, could someone please help me with them?       Log On


   



Question 151080: I dont understand how I should solve these by factoring; x^2-5x+6=0, 2x^2-9x-5=0, 3x^2+5x-2=0, could someone please help me with them?
Answer by mangopeeler07(462) About Me  (Show Source):
You can put this solution on YOUR website!
1. x^2-5x+6=0

Factor
(x-3)(x-2)=0

Set each expression equal to 0 and solve
x-3=0
x=3

x-2=0
x=2

So x=2; 3
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2.2x^2-9x-5=0

Factor
(2x+1)(x-5)=0

Set each expression equal to 0 and solve
2x+1=0
2x=-1
x=-1/2

x-5=0
x=5

So x=-1/2; 5
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3. 3x^2+5x-2=0

Factor
(3x-1)(x+2)=0

Set each expression equal to 0 and solve
3x-1=0
3x=1
x=1/3

x+2=0
x=-2

So x=1/3; -2