SOLUTION: I would appreciate if someone could help me with this problem. I am suppose to use FOIL to multiply which is (6x - 1)(3x - 4). Please help!!

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: I would appreciate if someone could help me with this problem. I am suppose to use FOIL to multiply which is (6x - 1)(3x - 4). Please help!!      Log On


   

Question 150959This question is from textbook Intermediate Algebra
: I would appreciate if someone could help me with this problem.
I am suppose to use FOIL to multiply which is (6x - 1)(3x - 4).
Please help!! This question is from textbook Intermediate Algebra

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%286x-1%29%283x-4%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%286x%29-1%29%28highlight%283x%29-4%29 Multiply the First terms:%286%2Ax%29%2A%283%2Ax%29=18%2Ax%5E2.


%28highlight%286x%29-1%29%283x%2Bhighlight%28-4%29%29 Multiply the Outer terms:%286%2Ax%29%2A%28-4%29=-24%2Ax.


%286x%2Bhighlight%28-1%29%29%28highlight%283x%29-4%29 Multiply the Inner terms:%28-1%29%2A%283%2Ax%29=-3%2Ax.


%286x%2Bhighlight%28-1%29%29%283x%2Bhighlight%28-4%29%29 Multiply the Last terms:%28-1%29%2A%28-4%29=4.


18%2Ax%5E2-24%2Ax-3%2Ax%2B4 Now collect every term to make a single expression.


18%2Ax%5E2-27%2Ax%2B4 Now combine like terms.


So %286x-1%29%283x-4%29 FOILS to 18%2Ax%5E2-27%2Ax%2B4.


In other words, %286x-1%29%283x-4%29=18%2Ax%5E2-27%2Ax%2B4.