SOLUTION: How do you factor by grouping, 48x^2y + 20xz +12xy + 5z, whats the answer?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: How do you factor by grouping, 48x^2y + 20xz +12xy + 5z, whats the answer?      Log On


   

Question 150932: How do you factor by grouping, 48x^2y + 20xz +12xy + 5z, whats the answer?
Found 2 solutions by jim_thompson5910, ankor@dixie-net.com:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
48x%5E2y%2B20xz%2B12xy%2B5z Start with the given expression

%2848x%5E2y%2B20xz%29%2B%2812xy%2B5z%29 Group the terms into two groups


4x%2812xy%2B5z%29%2B1%2812xy%2B5z%29 Factor out the GCF 4x out of the first group. Factor out the GCF 1 out of the second group


%284x%2B1%29%2812xy%2B5z%29 Since we have the common term 12xy%2B5z, we can combine like terms

So 48x%5E2y%2B20xz%2B12xy%2B5z factors to %284x%2B1%29%2812xy%2B5z%29

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
How do you factor by grouping, 48x^2y + 20xz +12xy + 5z,
;
Rearrange like this:
48x^2y + 12xy + 20xz + 5z
;
It's now apparent that we can factor 12xy and 5z like this;
12xy(4x + 1) + 5z(4x + 1)
:
Factor out (4x+1) and we have:
(4x + 1)(12xy + 5z)