SOLUTION: 2^2x=64

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 2^2x=64      Log On


   



Question 150891: 2^2x=64
Found 2 solutions by jim_thompson5910, Earlsdon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
2%5E%282x%29=64 Start with the given equation.


2%5E%282x%29=2%5E6 Rewrite 64 as 2%5E6


Since the bases are equal, the exponents are equal


2x=6 Set the exponents equal to one another.


x=%286%29%2F%282%29 Divide both sides by 2 to isolate x.


x=3 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=3

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
2%5E%282x%29+=+64 Substitute64+=+2%5E6
2%5E%282x%29+=+2%5E6 If the bases (2) are equal, then the exponents are equal.
2x+=+6 Divide both sides by 2.
x+=+3 Check:
2%5E%282x%29+=+64 Substitute x = 3.
2%5E%282%2A3%29+=+64
2%5E6+=+64
64+=+64