SOLUTION: Solve the system of linear equations by the substitution method.
5x + 4 y = 14
15x – 2y = 7
This is what I have so far...but I get lost somehow ..maybe I just don't undesta
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-> SOLUTION: Solve the system of linear equations by the substitution method.
5x + 4 y = 14
15x – 2y = 7
This is what I have so far...but I get lost somehow ..maybe I just don't undesta
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Question 150797: Solve the system of linear equations by the substitution method.
5x + 4 y = 14
15x – 2y = 7
This is what I have so far...but I get lost somehow ..maybe I just don't undestand the substitution method thoroughly
5x +4y = 14
-4y -4y
5x = 14 – 4y divide each by 5
5 5 5
x = 14 – 4y
5 5
5(14 – 4y) + 4y = 14
5 5
39 - 29y + 4y = 14
5 5
Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.
So let's isolate y in the first equation
Start with the first equation
Subtract from both sides
Rearrange the equation
Divide both sides by
Break up the fraction
Reduce
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Since , we can now replace each in the second equation with to solve for
Plug in into the first equation. In other words, replace each with . Notice we've eliminated the variables. So we now have a simple equation with one unknown.
Distribute to
Multiply
Multiply both sides by the LCM of 4. This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)