SOLUTION: y= M + A/N + A A = any coefficient M = degree of the numerator N = degree of the denominator If M = N, the horizontal asymptote is the ratio of its coefficient So, what if

Algebra ->  Rational-functions -> SOLUTION: y= M + A/N + A A = any coefficient M = degree of the numerator N = degree of the denominator If M = N, the horizontal asymptote is the ratio of its coefficient So, what if      Log On


   

Question 150689: y= M + A/N + A
A = any coefficient
M = degree of the numerator
N = degree of the denominator
If M = N, the horizontal asymptote is the ratio of its coefficient
So, what if M < N and M > N, how do you find the horizontal asymptote?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y= M + A/N + A
A = any coefficient
M = degree of the numerator
N = degree of the denominator
If M = N, the horizontal asymptote is the ratio of its coefficient
So, what if M < N and M > N, how do you find the horizontal asymptote?
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If M < N the ratio is 0; the horizontal asymptote is y = 0
Example: y = (x+2)/(x^2+4) ; ratio = 0/1 = 0
graph%28400%2C300%2C-10%2C10%2C-2%2C2%2C%28x%2B2%29%2F%28x%5E2%2B4%29%29
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If M > N the ratio is "undefined"; divide to find the slant asymptote.
Example: y = (x^2+4)/(x+2) ; ratio = 1/0 = undefined
Dividing you get y = (x-2) + 8/(x^2+4)
graph%28400%2C300%2C-20%2C10%2C-20%2C10%2C%28x%5E2%2B4%29%2F%28x%2B2%29%29
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Cheers,
Stan H.