SOLUTION: A man invests $10,000.00 in two enterprises. One enterprise yields 8% per year and the other yields 10% per year. If the income from both investments is $940.00 annually, how muc

Algebra ->  Human-and-algebraic-language -> SOLUTION: A man invests $10,000.00 in two enterprises. One enterprise yields 8% per year and the other yields 10% per year. If the income from both investments is $940.00 annually, how muc      Log On


   



Question 150683: A man invests $10,000.00 in two enterprises. One enterprise yields 8% per year and the other yields 10% per year. If the income from both investments is $940.00 annually, how much did he invest in each enterprise?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let a= the 8% per yr investment
Let b= the 10% per year investment
.08a+%2B+.1b+=+940
a+%2B+b+=+10000
b+=+10000+-+a
.08a+%2B+.1%2A%2810000+-+a%29+=+940
.08a+%2B+1000+-+.1a+=+940
-.02a+=+-60
a+=+60%2F.02
a+=+3000
And, since
a+%2B+b+=+10000,
3000+%2B+b+=+10000
b+=+7000
He invested $3,000 in the 8% investment
He invested $7,000 in the 10% investment
check:
.08a+%2B+.1b+=+940
.08%2A3000+%2B+.1%2A7000+=+940
240+%2B+700+=+940
940+=+940
OK