SOLUTION: how do you find the dimensions of the length and the width of a rectangle that is 2ft longer than its width if the ratio of the length to the width was 8 to 5?

Algebra ->  Proportions -> SOLUTION: how do you find the dimensions of the length and the width of a rectangle that is 2ft longer than its width if the ratio of the length to the width was 8 to 5?      Log On


   

Question 150681This question is from textbook elementary and intermediate algebra
: how do you find the dimensions of the length and the width of a rectangle that is 2ft longer than its width if the ratio of the length to the width was 8 to 5? This question is from textbook elementary and intermediate algebra

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Call the length l
Call the width w
l%2Fw+=+8%2F5
l+=+w+%2B+2
%28w+%2B+2%29%2Fw+=+8%2F5
Multiply both sides by 5w
5%2A%28w+%2B+2%29+=+8w
5w+%2B+10+=+8w
3w+=+10
w+=+10%2F3
l+=+10%2F3+%2B+2
l+=+10%2F3+%2B+6%2F3
l+=+16%2F3
The length is %2816%2F3%29%2A12+=+64in.
The width is %2810%2F3%29%2A12+=+40 in.
check answer:
The length is 24 in longer than the width
l%2Fw+=+8%2F5
64%2F40+=+8%2F5
5%2A64+=+8%2A40
320+=+320
OK
l+=+40+%2B+24
l+=+64
OK