SOLUTION: 1986 explosion at the Chernobyl nuclear power plant in the former soviet union sent about 1000 kilograms of radioactive cesium-137 into the atmosphere. The function f(x)=1000(0.5)^

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Question 150497: 1986 explosion at the Chernobyl nuclear power plant in the former soviet union sent about 1000 kilograms of radioactive cesium-137 into the atmosphere. The function f(x)=1000(0.5)^x/30 describes the amount, f(x) in kilograms, of cesium-137 remaining in Chernobyl x yrs after 1986. If even 100 kilograms of cesium-137 remain in Chernobyl's atmosphere, the area is considered unsafe for humans. find f(80) and determine if Chernobyl will be safe to live in 2066.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29+=+1000%2A%28.5%29%5E%28x%2F30%29
f%2880%29+=+1000%2A%28.5%29%5E%2880%2F30%29
f%2880%29+=+1000%2A%28.5%29%5E%282.6667%29
f%2880%29+=+1000%2A.157486
f%2880%29+=+157.486 answer
This is unsafe since it's more than 100 kg