SOLUTION: (c^-1)^-12(c^-5)^6/(c^-4)^0(c^3)^-3 answer 1/c^9 How do I get there? I am so lost! please help
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-> SOLUTION: (c^-1)^-12(c^-5)^6/(c^-4)^0(c^3)^-3 answer 1/c^9 How do I get there? I am so lost! please help
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Question 150455
:
(c^-1)^-12(c^-5)^6/(c^-4)^0(c^3)^-3
answer 1/c^9
How do I get there? I am so lost! please help
Answer by
jim_thompson5910(35256)
(
Show Source
):
You can
put this solution on YOUR website!
Let's break this problem down.
First let's simplify the numerator
Start with the first term in the numerator
Multiply the exponents using the identity
Multiply -1 and -12 to get 12
So
simplifies to
----------------------------------
Move onto the second term in the numerator
Multiply the exponents using the identity
Multiply -5 and 6 to get -30
So
simplifies to
=========================================================
So the expression
now becomes
=========================================================
Now let's simplify the denominator
Start with the first term in the denominator
Multiply the exponents using the identity
Multiply -4 and 0 to get 0
Raise c to the zeroth power to get 1
So
simplifies to
-------------
Move onto the second term in the denominator
Multiply the exponents using the identity
Multiply 3 and -3 to get -9
So
simplifies to
========================================
So after simplification, we go from
to
Start with the given expression.
Multiply 1 and
to get
Multiply the terms in the numerator by adding the exponents.
Add 12 to -30 to get -18
Divide the terms by subtracting the exponents.
Rewrite
to get
Add -18 to 9 to get -9
Rewrite
as
to make the exponent positive.
========================================================
Answer:
So
simplifies to