SOLUTION: In order to plot the graphs of the following functions, what do I do first? I am so lost! f(x)=7^x f(x)=4^x-3 f(x)=(1/5)^x f(x)=log3x Thanks for your help!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: In order to plot the graphs of the following functions, what do I do first? I am so lost! f(x)=7^x f(x)=4^x-3 f(x)=(1/5)^x f(x)=log3x Thanks for your help!      Log On


   



Question 150352: In order to plot the graphs of the following functions, what do I do first? I am so lost!
f(x)=7^x
f(x)=4^x-3
f(x)=(1/5)^x
f(x)=log3x
Thanks for your help!

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
plotting the graphs is straight forward (a graphing calculator would be a big help)
__ the f(x) values are on the vertical (y) axis and the x values are on the horizontal axis
__ find the f(x) values by "plugging in" values for x

1. f(x)=7^x __ when x=0, f(x)=1 (this is the y-intercept) __ when x is 1, f(x)=7
__ as x becomes a large NEGATIVE value, f(x) approaches zero (horizontal asymptote)

2. f(x)=4^(x-3) __ when x=3, the exponent is 0 so f(x)=1 __ when x=0, f(x)=4^(-3) or 1/64
__ same general shape as #1 with different y-intercept

3. f(x)=(1/5)^x __ when x=0, f(x)=1
__ as x becomes a large POSITIVE value, f(x) approaches zero (horizontal asymptote)
__ this graph is sort of a "mirror image" of #'s 1 and 2

4. logarithms are NOT defined for negative quantities, so this graph is only on the right-hand side of the vertical axis
__ as x approaches zero (very small fractions), f(x) approaches negative infinity (vertical asymptote)