SOLUTION: Maximum height. If a soccer ball is kicked straight up from the ground with an initial velocity of 32 feet per second, then its height above the earth in feet is given by s(t) = -1

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Question 150351This question is from textbook
: Maximum height. If a soccer ball is kicked straight up from the ground with an initial velocity of 32 feet per second, then its height above the earth in feet is given by s(t) = -16tē + 32t where t is time in seconds. Graph this parabola for 0≤ t ≤ 2.
What is the maximum height reached by the ball?
 This question is from textbook

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Maximum height. If a soccer ball is kicked straight up from the ground with an initial velocity of 32 feet per second, then its height above the earth in feet is given by s(t) = -16tē + 32t where t is time in seconds. Graph this parabola for 0≤ t ≤
:
y = s(t); x = t
Find y for x=0, x=.5, x=1, x=1.5, and x=2
:
+graph%28+300%2C+200%2C+-1%2C+3%2C+-10%2C+25%2C+-16x%5E2%2B32x%29+


2. What is the maximum height reached by the ball:
From the graph we can see max occurs when t = 1
Find s(1)
s(1) = -16(1^2) + 32(1)
s(1) = -16 + 32
s(1) = +16 ft max