SOLUTION: Please help me write (3-2i) in polar form. Here are the choices: 1. sqrt13(cos 33.7 degrees + i sin 33.7 degrees) 2. sqrt5(cos 326.3 degrees + i sin 326.3 degrees) 3. sqrt5(cos

Algebra ->  Trigonometry-basics -> SOLUTION: Please help me write (3-2i) in polar form. Here are the choices: 1. sqrt13(cos 33.7 degrees + i sin 33.7 degrees) 2. sqrt5(cos 326.3 degrees + i sin 326.3 degrees) 3. sqrt5(cos      Log On


   

Question 150312: Please help me write (3-2i) in polar form.
Here are the choices:
1. sqrt13(cos 33.7 degrees + i sin 33.7 degrees)
2. sqrt5(cos 326.3 degrees + i sin 326.3 degrees)
3. sqrt5(cos 33.7 degrees + i sin 33.7 degrees)
4. sqrt13(cos 326.3 degrees + i sin 326.3 degrees)
Thanks, Tami
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
abs%283-2i%29=sqrt%283%5E2%2B2%5E2%29=sqrt%2813%29
3-2i=sqrt%2813%29%283%2Fsqrt%2813%29-2i%2Fsqrt%2813%29%29
cos%28A%29=3%2Fsqrt%2813%29
A=33.7 or A=360-33.7=326.3
Since, 3-2i is in the 4th quadrant, then A=326.3
3-2i=sqrt%2813%29%28cos%28326.3%29%2Bi%2Asin%28326.3%29%29
Looks like #4.