SOLUTION: If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t - 16t2. Find the number of seconds the object is in the air before i
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-> SOLUTION: If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t - 16t2. Find the number of seconds the object is in the air before i
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Question 150310: If an object is thrown upward with an initial velocity of 64 ft/sec, its height after t sec is given by h = 64t - 16t2. Find the number of seconds the object is in the air before it hits the ground.
I figure that it would work with d=rt but I don't know how to convert it to this assignment. what throws me off is the h=64t-16t2... Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! because of gravitational acceleration, r is constantly changing __ that makes d=rt not useful in this situation
when it is on the ground, h=0 __ so we can substitute and solve
0=64t-16t^2 __ factoring __ 0=(16t)(4-t)
0=16t __ dividing by 16 __ 0=t __ this is the beginning of the "flight"
0=4-t __ adding t __ t=4 __ this is the "flight" time
