SOLUTION: Could someone help me with this problem? I know how to graph, but when the function deals with fractions I get a bit confused. I have indicated the answers and want to know if my

Algebra ->  Graphs -> SOLUTION: Could someone help me with this problem? I know how to graph, but when the function deals with fractions I get a bit confused. I have indicated the answers and want to know if my      Log On


   

Question 150225: Could someone help me with this problem? I know how to graph, but when the function deals with fractions I get a bit confused. I have indicated the answers and want to know if my answers are correct. I would appreciate help to see if I solved the problem correctly.
The problem states:
Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
f(x)=1/2(x+6)^2+4
The vertex is: (-6,4)
The line of symmetry is x= -6
What is the maximum/minimum value of f(x)? 4
Is the value, f(-6)=4, a maximum or minimum? Maximum
Note: The 1/2 means one half, not 1 divided by 2, just to clarify the problem.
Did I solve this problem correctly? Thank you for your help.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Here's a graph of the function
y=%28x%2B6%29%5E2%2F2%2B4
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Let's check your answers.
1. Vertex:(-6,4). Correct.
2. Line of symmetry:x=-6. Correct.
3. Max/Min value:f(-6)=4. Correct.
4. Max or Min:Maximum. Incorrect.
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.
.
This is determined by the sign of the coefficient of x%5E2
If it's positive, like in this case(1%2F2), the parabola opens up, minimum value occurs.
If it's negative, unlike this case, the parabola opens down, maximum value occurs.