SOLUTION: x^2 - 10x + 35 = sorry, I didn't pose the problem properly. Thank you for your time and patience.

Algebra ->  Exponents -> SOLUTION: x^2 - 10x + 35 = sorry, I didn't pose the problem properly. Thank you for your time and patience.      Log On


   

Question 150070: x^2 - 10x + 35 =
sorry, I didn't pose the problem properly. Thank you for your time and patience.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 - 10x + 35 =
----
x^2 - 10x + 35 = 0 ??
I'll assume equal zero, and solve for x.
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-10x%2B35+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-10%29%5E2-4%2A1%2A35=-40.

The discriminant -40 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -40 is + or - sqrt%28+40%29+=+6.32455532033676.

The solution is , or
Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-10%2Ax%2B35+%29