SOLUTION: Hello, I could use some help with this problem. Simplify the expression. (6 - <i>i</i>) / (2 + 3<i>i</i>) Thank you!

Algebra ->  Radicals -> SOLUTION: Hello, I could use some help with this problem. Simplify the expression. (6 - <i>i</i>) / (2 + 3<i>i</i>) Thank you!      Log On


   



Question 149993: Hello,
I could use some help with this problem.
Simplify the expression.
(6 - i) / (2 + 3i)
Thank you!

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
The idea behind simplifying expressions containing complex numbers in their denominator, such as you have here, is to change the denominator into a "real" number.
You do this by multiplying the top and bottom of your expression by the complex conjugate of the denominator.
The conjugate of a complex number (a+bi) is simply (a-bi), so, in your problem,...
%286-i%29%2F%282%2B3i%29 The denominator is the complex number (2+3i) and its conjugate is (2-3i), so let's proceed...
%286-i%29highlight%28%282-3i%29%29%2F%282%2B3i%29highlight%28%282-3i%29%29 ...as you can see, we are really multiplying your original expression by %282-3i%29%2F%282-3i%29+=+1 and so its value does not change.
Let's perform the indicated multiplication using the FOIL method.
Simplifying all of this and recalling that i%5E2+=+-1, we get:
%2812-18i-2i%2B3i%5E2%29%2F%284-6i%2B6i-9i%5E2%29=%289-20i%29%2F13