Question 149976: These problems are really giving me some trouble, will someone please help!
If:
tanA=(-2/3) and 90 degrees < A < 180 degrees, find sinA.
Thank you again for your time, Natalie
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! tanA=(-2/3) and 90 degrees < A < 180 degrees, find sin A.
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Use the inverse tangent button on your calculator to get:
tan^-1(-2/3) = -33.69.. degree.
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Then, since tangent is negative in 2nd and 4th quadrants",
add 180 degrees to -33.69... to get 146.31 degrees.
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Cheers,
Stan H.
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