SOLUTION: Can you please help with this 3 part problem. The first part is to solve 3x+4y=8 for y The second part is when graphed this equation would be a line. By examining your answer to

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Can you please help with this 3 part problem. The first part is to solve 3x+4y=8 for y The second part is when graphed this equation would be a line. By examining your answer to       Log On


   



Question 149828This question is from textbook
: Can you please help with this 3 part problem. The first part is to solve 3x+4y=8 for y The second part is when graphed this equation would be a line. By examining your answer to part a, what is the slope and y-intercept of this line? The third part is using your answer from part a, find the corresponding value of y when x =8 This question is from textbook

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Can you please help with this 3 part problem. The first part is to solve 3x+4y=8 for y The second part is when graphed this equation would be a line. By examining your answer to part a, what is the slope and y-intercept of this line? The third part is using your answer from part a, find the corresponding value of y when x =8
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1. Solving for y means getting the eqn into the form: y =
3x+4y = 8
Subtract 3x from both sides
4y = -3x + 8
Divide by 4
y = (-3/4)x + 2
That's all.
2. This is the classic slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept (where the line crosses the y-axis, which is also the value at x = 0)
So the slope is -3/4, and the y-intercept is 2, or the point (0,2).
3. Just evaluate y = (-3/4)x + 2 for x = 8
y = (-3/4)*8 + 2
y = -6 + 2
y = -4 at x = 8, the point (8,-4)