SOLUTION: The vectors (8,0) and (3,4) form a paralellogram. Find the lengths of its altitudes. I don't know how to generate the algebraic equations to solve this one.

Algebra ->  Formulas -> SOLUTION: The vectors (8,0) and (3,4) form a paralellogram. Find the lengths of its altitudes. I don't know how to generate the algebraic equations to solve this one.      Log On


   



Question 149699: The vectors (8,0) and (3,4) form a paralellogram. Find the lengths of its altitudes. I don't know how to generate the algebraic equations to solve this one.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
First plot the two points (0,0) and (3,4). Now draw a right triangle with the hypotenuse that goes through the two points. With the use of pythagoreans theorem, we find that the hypotenuse is 5 units (since sqrt%283%5E2%2B4%5E2%29=sqrt%289%2B16%29=sqrt%2825%29=5). So our drawing looks like this:

Photobucket - Video and Image Hosting

Now if draw the vectors and draw the parallelogram, we can see that the height of the parallelogram is the y-coordinate of the point (3,4). So the first height is 4.

Photobucket - Video and Image Hosting

So from the drawing, we see that the base is 8 units and the height is 4 units.


Now if we compute the area, we get:

A=b%2Ah=8%2A4=32


Now let the vector from (0,0) to (3,4) be the new base. So the base is now 5. The area is still 32. So this means that

32=5h

Solving for h, we get h=32%2F5=6.4

So the second height is 6.4