SOLUTION: A rectangular box has dimensions 1 1/2 feet x 2 feet x 3 feet. What is the length of the longest object that can be put in the box, if the object can be placed in any position? Th
Algebra ->
Rectangles
-> SOLUTION: A rectangular box has dimensions 1 1/2 feet x 2 feet x 3 feet. What is the length of the longest object that can be put in the box, if the object can be placed in any position? Th
Log On
Question 149659: A rectangular box has dimensions 1 1/2 feet x 2 feet x 3 feet. What is the length of the longest object that can be put in the box, if the object can be placed in any position? This comes from the THEA Practice Test. Thanks Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! A rectangular box has dimensions 1 1/2 feet x 2 feet x 3 feet. What is the length of the longest object that can be put in the box, if the object can be placed in any position?
.
The diagonal of the 2x3 is:
x^2 = 2^2 + 3^2
x^2 = 4 + 9
x^2 = 13
x = sqrt(13)
.
The diagonal of the 1.5xsqrt(13) is:
x^2 = 1.5^2 + sqrt(13)^2
x^2 = 2.25 + 13
x^2 = 15.25
x = 3.91 inches
