SOLUTION: Could you please help me with figuring out how to do this?
The length of a top of a board is 6m greater than width. The area is 72m^2. Find the diminsions for width of board and
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The length of a top of a board is 6m greater than width. The area is 72m^2. Find the diminsions for width of board and
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Question 149613: Could you please help me with figuring out how to do this?
The length of a top of a board is 6m greater than width. The area is 72m^2. Find the diminsions for width of board and length of board.
Thank you for any help. Found 2 solutions by jim_thompson5910, stanbon:Answer by jim_thompson5910(35256) (Show Source):
Since the "length of a top of a board is 6m greater than width", this means that the first equation is . Also, since the "area is 72m^2", this tells us that or
Start with the given equation.
Plug in and .
Distribute
Subtract 72 from both sides.
Let's use the quadratic formula to solve for W
Start with the quadratic formula
Plug in , , and
Square to get .
Multiply to get
Rewrite as
Add to to get
Multiply and to get .
Take the square root of to get .
or Break up the expression.
or Combine like terms.
or Simplify.
Since a negative width is not possible, the only possible width is
You can put this solution on YOUR website!
The length of a top of a board is 6m greater than width. The area is 72m^2. Find the diminsions for width of board and length of board.
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Let width be "x" meters.
Then length is "x+6" meters.
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Area = width*length = 72m^2
x(x+6) = 72
x^2+6x-72 = 0
(x+12)(x-6) = 0
Positive solution:
x = 6 meters (width)
x+6 = 12 meters (length)
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Cheers,
Stan H.