Question 149454: 1)line l goes through (1,3) and is parallel to the line through (4,3) and (-3,1) FInd the slope of l.
the answer I got was 2/7 is this correct?
2)line l goes through the point (5,-2) and is perpendicular to the line through (-2,1)and (-4,-2) Find the slope of l
the answer I got was -3/2 is this correct?
3)Write the equation y=1/3x-2 in standard form using only integers and a positive coefficent for x
The answer I got was x+3y=6 is this correct?
4) A Line that goes through (-1,-3)and has a slope of 4.
My answer is y=4x-3 is this correct?
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! 1) correct
2) You're on the right track. The slope through (-2,1)and (-4,-2) is 3/2. So flip the fraction and change the sign to get -2/3. So the perpendicular slope is -2/3
3) Close, but you forgot to multiply the term "3y" by negative 1 (since you multiplied the "x" term by -1). So the correct equation is x-3y=6
4)
If you want to find the equation of line with a given a slope of  which goes through the point ( , ), you can simply use the point-slope formula to find the equation:
---Point-Slope Formula---
 where  is the slope, and ) is the given point
So lets use the Point-Slope Formula to find the equation of the line
 Plug in  ,  , and  (these values are given)
 Rewrite  as 
 Rewrite  as 
 Distribute
 Multiply and  to get
 Subtract 3 from both sides to isolate y
 Combine like terms and to get
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Answer:
So the equation of the line with a slope of which goes through the point (,) is:
which is now in  form where the slope is and the y-intercept is 
Notice if we graph the equation and plot the point (,), we get (note: if you need help with graphing, check out this solver)
 Graph of through the point (,)
and we can see that the point lies on the line. Since we know the equation has a slope of and goes through the point (,), this verifies our answer.
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