SOLUTION: THE PERIMETER OF A RECTANGLE IS 96. THE LENGTH OF THE RECTANGLE IS SIX LESS THAN TWICE THE WIDTH. FIND THE DIMENSIONS OF THE RECTANGLE.

Algebra ->  Rectangles -> SOLUTION: THE PERIMETER OF A RECTANGLE IS 96. THE LENGTH OF THE RECTANGLE IS SIX LESS THAN TWICE THE WIDTH. FIND THE DIMENSIONS OF THE RECTANGLE.      Log On


   

Question 149450This question is from textbook page 397
: THE PERIMETER OF A RECTANGLE IS 96. THE LENGTH OF THE RECTANGLE IS SIX LESS THAN TWICE THE WIDTH. FIND THE DIMENSIONS OF THE RECTANGLE. This question is from textbook page 397

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
P=2L+2W
96=2(2W-6)+2W
96=4W-12+2W
96=4W-12
4W=96+12
4W=108
W=108/4
W=18 FOR THE WIDTH.
2*18-6=36-6=30 FOR THE LENGTH.
PROOF:
96=2*30+2*18
96=60+36
96=96