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| Question 149395:  What type of solution do you get for quadratic equations where D<0?  Give reasons for your answer.  Also provide an example of such a quadratic equation and find the solution of the equation.
 Found 2 solutions by  stanbon, jim_thompson5910:
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! What type of solution do you get for quadratic equations where D<0?  Give reasons for your answer.  Also provide an example of such a quadratic equation and find the solution of the equation. ----------------
 By "D" I assume mean the discriminant, b^2-4ac.
 If D<0 the quadratic equation will produce two
 solutions that are both complex numbers because
 you will be taking the square root of a negative
 in the process.
 ---------------------------
 Example:
 y = x^2-x+4
 D = b^2-4ac = 1-4*1*4 = -15
 ---------
 Solutions:
 x = [1 +- sqrt(-15)]/2
 x = [1 + isqrt(15)]/2 or x = [1- i sqrt(15)]/2
 ==========================
 Cheers,
 Stan H.
Answer by jim_thompson5910(35256)
      (Show Source): 
You can put this solution on YOUR website! If  , then the quadratic will have two complex (ie non real) solutions. 
 For example, let's find the discriminant for
   
 
 From
  we can see that  ,  , and   
 
 
  Start with the discriminant formula 
 
 
  Plug in  ,  , and   
 
 
  Square  to get   
 
 
  Multiply  to get   
 
 
  Subtract  from  to get   
 
 Since the discriminant is less than zero, this means that there are two complex solutions
 
 
 Now let's use the quadratic formula to find the solutions of
   
 
 
  Start with the quadratic formula 
 
 
  Plug in  ,  , and   
 
 
  Square  to get  . 
 
 
  Multiply  to get   
 
 
  Subtract  from  to get   
 
 
  Multiply  and  to get  . 
 
 
  Take the square root of  to get  . 
 
 
  or  Break up the expression. 
 
 
  or  Break up the fraction for each case. 
 
 
  or  Reduce. 
 
 So our answers are
  or   
 
 Since our answers are complex, this verifies our original claim.
 
 
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