SOLUTION: The length of a rectange is 6in more than 3 times its width. If the width were increased by 4 and the length decreased by 10, the area of the new rectangle would equal the area of
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Question 149381: The length of a rectange is 6in more than 3 times its width. If the width were increased by 4 and the length decreased by 10, the area of the new rectangle would equal the area of the orignal rectangle. Find the length and width of the original rectangle. Found 2 solutions by jojo14344, mangopeeler07:Answer by jojo14344(1513) (Show Source):
You can put this solution on YOUR website! Let , with following conditions: ,
So, ---->
.
Let with following conditions:
So, ---->
.
Equating the 2 Areas because of the conditions, becoming , rearranging thereafter: ---->
Going back to the old condition for --->
In doubt? Go back
Also,
Thank you,
Jojo
You can put this solution on YOUR website! l=3w+6------------------The length of a rectange is 6in more than 3 times its width
w=w---------------------The width
w(3w+6)=(w+4)(3w-4)-----------------If the width were increased by 4 and the length decreased by 10, the area of the new rectangle would equal the area of the orignal rectangle
Distribute
3w^2+6w=3w^2+8w-16
Subtract 3w^2 from both sides
6w=8w-16
Subtrat 8w from both sides
-2w=-16
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