SOLUTION: Multiplying and Dividing Rational Expressions.... 1)(16x^2/y^4)Multiplied by (5x^2/y^2) 2) (6x^5y^3/5z^3)Multiplied by(6x^4/5yz^4) 3) (x^2+7x+12/x+4) Multiplied by (

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Multiplying and Dividing Rational Expressions.... 1)(16x^2/y^4)Multiplied by (5x^2/y^2) 2) (6x^5y^3/5z^3)Multiplied by(6x^4/5yz^4) 3) (x^2+7x+12/x+4) Multiplied by (      Log On


   



Question 149353: Multiplying and Dividing Rational Expressions....
1)(16x^2/y^4)Multiplied by (5x^2/y^2)


2) (6x^5y^3/5z^3)Multiplied by(6x^4/5yz^4)

3) (x^2+7x+12/x+4) Multiplied by (1/x+3)

4) (25xy^2/7z) Divided By (5x^2y^2/14z^2)

5)(x^2-12x+32/x^2-6x-16)Divided by (x^2-x-12/x^2-5x-24)


I am aware that when you multiply and divide ration expressions the denominators must be the same, but I am unaware as to how to go about this. Can you please help me if at all possible with these questions so I can further apply these methods to the rest of my homework.......

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
When add or subtract fraction, the denominators must be the same. That is not the case when you multiply or divide.
If I asked you to multiply 1%2F3 * 1%2F2 = 1%2F3+%2A+1%2F2 you would say 1%2F6. No need to get a common denominator. Just multiply the numerators together. Then put that result over the product of the denominators. Then simplify if possible.
So let;s do the first one.
%2816x%5E2%2Fy%5E4%29+%2A+%285x%5E2%2Fy%5E2%29
%2816x%5E2+%2A+5x%5E2%29+%2F%28y%5E4+%2A+y%5E2%29
%2880x%5E2+%2A+x%5E2%29+%2F%28y%5E6%29
80x%5E4++%2Fy%5E6
I'll leave problem 2 for you.
Let's look at problem 3.
%28%28x%5E2%2B7x%2B12%29%2F%28x%2B4%29%29+%2A%281%2F%28x%2B3%29%29
%28%28x%2B4%29%28x%2B3%29%2F%28x%2B4%29%29+%2A%281%2F%28x%2B3%29%29
%28x%2B3%29+%2A+%281%2F%28x%2B3%29%29
1

To do division, just remember that dividing a fraction by a fraction is the same as multiplying the first fraction by the reciprocal of the second one.
So, for problem 4
%28%2825xy%5E2%29%2F7z%29+%2F%28%285x%5E2y%5E2%29%2F14z%5E2%29
%28%2825xy%5E2%29%2F7z%29+%2A+%2814z%5E2%2F%285x%5E2y%5E2%29%29
And now use the same process used in the previous problems to solve.
Same for 5. Just remember to factor and cancel before getting too far into the work