SOLUTION: Problem A sheet metal worker is planning to make an open top box by cutting equal squares(x-in by x-in) from the corners of a 10in by 14 in piece of copper. A second box is to be m
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Question 149245: Problem A sheet metal worker is planning to make an open top box by cutting equal squares(x-in by x-in) from the corners of a 10in by 14 in piece of copper. A second box is to be made in the same manner from an 8 in by 10 in piece of aluminum, but its height is to be one half that of the first box.
1.Find the polynomial function for the volume of each box
2.find the values of x for which the copper box is 72 cubic inch larger than the aluminum box
3.write the difference between the two volumes (d) as a function of x
4.find d for x=1.5
5.for what value of x is the difference between the two volumes the largest
6. explain the steps to solve this problem Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! i) Problem: A sheet metal worker is planning to make an open-top box by cutting equal squares (x-in. by x-in.) from the corners of a 10-in. by 14-in. piece of copper. A second box is to be made in the same manner from an 8-in. by 10-in. piece of aluminum, but its height is to be one-half that of the first box.
:
(1)Find a polynomial function for the volume of each box.
:
1st box dimensions: (10-2x) by (14-2x) by x
Vol = x*(10-2x)*(14-2x)
FOIL
f(x) = x(140 - 48x + 4x^2)
f(x) = 4x^3 - 48x^2 + 140x
:
2nd box cut out will be .5x in. by .5x in.,(height 1/2 the 1st box), therefore:
the dimensions will be:
(10-x) by (8-x) by .5x
Vol = .5x*(10-x)*(8-x)
FOIL
f(x) = .5x(80 - 18x + x^2)
f(x) = .5x^3 - 9x^2 + 40x
:
:
(2)Find the values of x for which the copper box is 72 cubic in. larger than the aluminum box.
:
Big box vol - small box vol = 72 cu in
(4x^3 - 48x^2 + 140x) - (.5x^3 - 9x^2 + 40x) = 72
Remove brackets
4x^3 - 48x^2 + 140x - .5x^3 + 9x^2 - 40x = 72
Group like terms
4x^3 - .5x^3 - 48x^2 + 9x^2 + 140x - 40x - 72 = 0
:
3.5x^3 - 39x^2 + 100x - 72 = 0
:
Solve this by graphing y = 3.5x^3 - 39x^2 + 100x - 72
:
The integer solution x = 2; & x ~ 1.3; the third solution x ~ 7.8 isn't reasonable
:
(3)Write the difference between the two volumes (d) as a function of x.
d(x) = (4x^3 - 48x^2 + 140x) - (.5x^3 - 9x^2 + 40x)
which is
d(x) = 3.5x^3 - 39x^2 + 100x
:
(4)Find d for x=1.5
d(x) = 3.5(1.5^3) - 39(1.5^2) + 100(1.5)
d(x) = 3.5(3.375) - 39(2.25) + 150
d(x) = 11.8125 - 87.75 + 150
d(x) = 74.0625
:
(5)For what value of x is the difference between the two volumes the largest?
Graph d(x) = 3.5x^3 - 39x^2 + 100x:
:
Greatest difference appears to be at x = 1.7 which is a difference of about 74.5
