SOLUTION: Marcus saved 20 coins consisting of 25 cents and Php 1 coins. How many of each kind did he have if the coins amounted to Php 10.25?

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Question 149202: Marcus saved 20 coins consisting of 25 cents and Php 1 coins. How many of each kind did he have if the coins amounted to Php 10.25?
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
Let "x" = P 0.25
"y" = P 1.00
We know we have 20 coins in total, so x%2By=20 right? -----> eqn 1
Also, 0.25x + 1.00y = P 10.25 -------> eqn 2
In eqn 1, we get y=20-x and substitute it in eqn 2,
Continuing,
0.25x + 1.00(20-x) =10.25
0.25x + 20 - 1x = 10.25
re-arranging, 20-10.25 = x-0.25x
0.75x = 9.75
x=13 ------------> no. of P 0.25 coins
In eqn 1, 13+%2B+y+=20, y=7 -----> no. of P1.00
In doubt? Go back eqn 2,
(0.25*13) + (1*7) = 10.25
3.25 + 7 = 10.25
P10.25=P10.25
Thank you,
Jojo