Question 14916: Twice the greater of two consecutive odd intgers is 13 less than three times the lesser. Find the integers.
Answer by elima(1433)   (Show Source):
You can put this solution on YOUR website! First of all two consecutive integers would be:
x, x+2;
Now we have twicw the greater; which the greater would be;
x+2; so twice that = 2(x+2);
And the word is in a word problem means =;
So far we have;
2(x+2)=
Now 13 less than(-) 3 times(*) the lesser, the lesser integer would be x;
so we have 3x-13
Now we put those together and we have;
2(x+2)=3x-13;
Now lets solve;
2x+4=3x-13, add 13 to both sides;
2x+4+13=3x-13+13
2x+17=3x; now subtract 2x from both sides;
2x+17-2x=3x-2x
17=x
So x being the lesser of the two odd integers = 17;
x+2=17+2=19
So the odd integers are 17,19
Hope you understand
=)
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