SOLUTION: Solve each system by substitution 1)y=2x-8 4x+3y=1 2)y=x-5 3x-4(y-2)=28-x

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Question 149120: Solve each system by substitution


1)y=2x-8
4x+3y=1

2)y=x-5
3x-4(y-2)=28-x


Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.y=2x-8
2.4x%2B3y=1
In the substitution method, you use one equation to get an expression of one variable in terms of the other variable.
You then substitute this value into the remaining equation.
In the first case, y is already in terms of x in eq. 1.
Substitute this expression for y in eq. 2 and solve for x.
2.4x%2B3y=1
4x%2B3%282x-8%29=1
4x%2B6x-24=1
10x-24=1
10x=25
x=25%2F10
x=5%2F2
Now use this in either eq. 1 or 2 to get y.
1.y=2x-8
y=2%285%2F2%29-8
y=5-8
y=-3
.
.
.
1.y=x-5
2.3x-4%28y-2%29=28-x
Similarly,
2.3x-4%28y-2%29=28-x
3x-4%28x-5-2%29=28-x
3x-4%28x-7%29=28-x
3x-4x%2B28=28-x
3x-4x%2B28=28-x
-x%2B28=-x%2B28
0=0
True, but not helpful for a solution.
When this happens, eq. 1 and eq. 2 are actually the same equation.
Let's look at eq. 2 more closely,
2.3x-4%28y-2%29=28-x
3x-4y%2B8=28-x
3x-4y%2B8=28-x
-4y=20-4x
y=%2820-4x%29%2F%28-4%29
y=-5%2Bx
y=x-5
Since eq. 1 and eq. 2 are the same, this is a dependent system of equations.