Question 148958: the small soo at the park charges $12 for adult admission, $8 for child admission and $5 for senior admission. for one day, the zoo collected $839 and admitted 98 visitors. If the adult admission is 5 more than the senior admission, how many persons of each category were admitted on this day?
Answer by mangopeeler07(462) (Show Source):
You can put this solution on YOUR website! x=number of adults
y=number of kids
z=number of seniors
coefficient=admission price
x=z+5
12x+8y+5z=839
x+y+z=98
Solve for y in the third equation
y=98-z-x
Plug in x
y=98-z-z-5
Plug in values for y and x in the second equation
12(z+5)+8(98-2z-5)+5z=839
Distribute
12z+60+784-16z-40+5z=839
Combine like terms
z+804=839
Subtract 804
z=35
number of seniors=35
x=z+5
Plug in z
x=35+5
x=40
number of adults=40
x+y+z=98
40+y+35=98
Combine like terms
75+y=98
Subtract 75 from both sides
y=23
number of kids=23
So,
# of seniors=35
# of adults=40
# of kids=23
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