Question 148833: If P(y)=10y^2+4
Q(y)=y^3-5y^2+3y+7
Find 3P(y)+q(y)
3(10y^2+4+y^3-5y^2+3y+7)
5y^2+11+y^3+3y
5y^2+11+y^3+3y
Is this correct? Answer by nabla(475) (Show Source):
You can put this solution on YOUR website! 3P(y)=30y^2+12
Q(y)=y^3-5y^2+3y+7
So, these two added together are:
3P(y)+Q(y)=y^3+25y^2+3y+19.