SOLUTION: I can't seem to get this one. Find the vertex of the parabola. y = -2x2 + 12x - 13 Help! Ellen

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I can't seem to get this one. Find the vertex of the parabola. y = -2x2 + 12x - 13 Help! Ellen      Log On


   

Question 148811: I can't seem to get this one.
Find the vertex of the parabola. y = -2x2 + 12x - 13
Help!
Ellen
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the vertex of the parabola. y = -2x^2 + 12x - 13
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There are several ways to do this; one is to complete the square.
-2x^2 + 12x - 13 = y
2x^2 - 12x = -(y+13)
Complete the square on the x-terms:
2(x^2 - 6x + 9) = -y-13+18
Factor:
2(x-3)^2 = -(y-5)
Vertex is at x=3, y=5
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graph%28400%2C300%2C-10%2C10%2C-20%2C20%2C-2x%5E2%2B12x-13%29
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Cheers,
Stan H.