Question 148767: George Lucas pioneered the use of digital movie cameras with the most recent Star Wars film. Assume that Lucas's camera has a swappable 80 GB hard drive (remember: 1 GB = 1024 MB, 1 MB = 1024 KB, 1 KB = 1024 Bytes, and 1 Byte = 8 bits), that it records each pixel in x-bit color, that there are 26 frames recorded per second, and that each frame is recorded in 1600x1200 resolution.
Create a polynomial function that gives the number of minutes of video that can be recorded before swapping in a new hard drive, as a function of x (the number of bits used to encode the color of each pixel)
Evaluate this function for x = 32 (32-bit true color)
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! George Lucas pioneered the use of digital movie cameras with the most recent Star Wars film. Assume that Lucas's camera has a swappable 80 GB hard drive (remember: 1 GB = 1024 MB, 1 MB = 1024 KB, 1 KB = 1024 Bytes, and 1 Byte = 8 bits), that it records each pixel in x-bit color, that there are 26 frames recorded per second, and that each frame is recorded in 1600x1200 resolution.
.
Create a polynomial function that gives the number of minutes of video that can be recorded before swapping in a new hard drive, as a function of x (the number of bits used to encode the color of each pixel)
.
Evaluate this function for x = 32 (32-bit true color)
.
Let's take this one step at a time.
Each FRAME is 1600x1200
That's 1920000 bits
.
Each bit has 'x' bits of color:
1920000x
.
There are 26 frames per seconds:
26*1920000x
49920000x bits per second
.
In bytes it would be:
49920000x/8
6240000x bytes per second
.
or, in MB (mega bytes):
6240000x/1000000
6.24x MB per second
.
There are 60 seconds per minute:
60 * 6.24x
374.4x MB per minute
.
Or in GB (giga bytes)
374.4x/1000
.3744x GB per minute
.
He has an 80 GB hard drive, so the formula is:
"minutes he can record" = 80/(.3744x)
.
If x = 32
80/(.3744(32))
=80/(11.9808)
=6.68 minutes
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