SOLUTION: two circles of radius 10 cm are drawn so that their centers are 12 cm apart. The two points of intersection determine a common chord. Find the length of this chord. thx

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Question 148658: two circles of radius 10 cm are drawn so that their centers are 12 cm apart. The two points of intersection determine a common chord. Find the length of this chord.
thx

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
two circles of radius 10 cm are drawn so that their centers are 12 cm apart. The two points of intersection determine a common chord. Find the length of this chord.
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If you draw them, you'll see that there is a triangle formed by the 2 centers and one of the points of intersection of the circle. The chord is perpendicular to the line connecting the 2 circles, so it makes a right triangle with the radius and 1/2 of the line between the centers.
The radius is the hypotenuse = 10.
1/2 of the line connecting the centers = 6.
So 1/2 the chord = sqrt%2810%5E2+-+6%5E2%29
C/2= sqrt%2864%29
C/2 = 8
The chord = 16.