SOLUTION: a/b+b/c / c/d+d/e

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: a/b+b/c / c/d+d/e      Log On


   

Question 148531This question is from textbook Algebra 1 california edition
: a/b+b/c / c/d+d/e This question is from textbook Algebra 1 california edition

Answer by mangopeeler07(462) About Me  (Show Source):
You can put this solution on YOUR website!
Figure out %28a%2Fb%29%2B%28b%2Fc%29. Times a/b by c/c and b/c by b/b. Get %28ac%2Fbc%29%2B%28b%5E2%2Fbc%29 Add the numerators and get %28ac%2Bb%5E2%29%2Fbc.

No do c/d+d/e. Same pattern, so you will get %28ce%2Bd%5E2%29%2Fde. Flip this one and get de%2F%28ce%2Bd%5E2%29.

Multiply the two new fractions together:
%28%28ac%2Bb%5E2%29%2Fbc%29%28de%2F%28ce%2Bd%5E2%29%29.

And get %28ac%2Bb%5E2%28de%29%29%2F%28bc%29%28ce%2Bd%5E2%29